Select the reaction which will be favoured in | vedclass

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Question

(B) reaction is favoured in the forward direction if a stronger acid reacts with a stronger base to form a weaker acid and a weaker base. In option $B

Vedclass · Accepted Answer

Anilinium ion + $o$-toluidine $\rightleftharpoons$ Aniline + $o$-toluidinium ion

Vedclass · Answer

(B) reaction is favoured in the forward direction if a stronger acid reacts with a stronger base to form a weaker acid and a weaker base. In option $B$,the reaction is: $C_6H_5NH_3^+ + o-CH_3C_6H_4NH_2 \rightleftharpoons C_6H_5NH_2 + o-CH_3C_6H_4NH_3^+$. Here,$o$-toluidine $(o-CH_3C_6H_4NH_2)$ is a stronger base than aniline $(C_6H_5NH_2)$ due to the electron-donating $+I$ effect of the $-CH_3$ group. Therefore,$o$-toluidine will accept the proton more readily than aniline,shifting the equilibrium to the right (forward direction).

Select the reaction which will be favoured in the forward direction.

Similar Questions

Complete the following Acid-Base reactions and identify each reactant as an Acid or a Base:
$(i)$ $CH_3NH_2 + H_2O$
$(ii)$ $CO_2 + H_2O$
$(iii)$ $H_2PO_4^- + CO_3^{2-}$
$(iv)$ $NH_2NH_2 + H_2O$
$(v)$ $C_6H_6 + NO_2^+$
$(vi)$ $C_6H_6 + NH_2^-$

Which two sets of reactants best represent the amphoteric character of $Zn(OH)_2$?
Set $1$ : $Zn(OH)_{2(s)}$ and $OH^{-}_{(aq)}$
Set $2$ : $Zn(OH)_{2(s)}$ and $H_2O_{(l)}$
Set $3$ : $Zn(OH)_{2(s)}$ and $H^{+}_{(aq)}$
Set $4$ : $Zn(OH)_{2(s)}$ and $NH_{3(aq)}$

Which of the following is an amphoteric substance?

The conjugate base of $NH_3$ is:

The solvent which neither accepts a proton nor donates a proton is called:

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